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1105425114433 is a prime number
BaseRepresentation
bin10000000101100000011…
…110001010010101000001
310220200021222101010122221
4100011200132022111001
5121102402312130213
62203454132331041
7142602315303463
oct20054036122501
93820258333587
101105425114433
11396898727842
1215a2a4773a81
1380319a2c763
143b707bca133
151db4bdcc38d
hex1016078a541

1105425114433 has 2 divisors, whose sum is σ = 1105425114434. Its totient is φ = 1105425114432.

The previous prime is 1105425114383. The next prime is 1105425114517. The reversal of 1105425114433 is 3344115245011.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 869998311169 + 235426803264 = 932737^2 + 485208^2 .

It is a cyclic number.

It is not a de Polignac number, because 1105425114433 - 229 = 1104888243521 is a prime.

It is a super-2 number, since 2×11054251144332 (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1105425114533) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 552712557216 + 552712557217.

It is an arithmetic number, because the mean of its divisors is an integer number (552712557217).

Almost surely, 21105425114433 is an apocalyptic number.

It is an amenable number.

1105425114433 is a deficient number, since it is larger than the sum of its proper divisors (1).

1105425114433 is an equidigital number, since it uses as much as digits as its factorization.

1105425114433 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 28800, while the sum is 34.

The spelling of 1105425114433 in words is "one trillion, one hundred five billion, four hundred twenty-five million, one hundred fourteen thousand, four hundred thirty-three".