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1105481348753 is a prime number
BaseRepresentation
bin10000000101100011110…
…100101011011010010001
310220200102220012010122112
4100011203310223122101
5121103011211130003
62203503501515105
7142603600265105
oct20054364533221
93820386163575
101105481348753
11396917446491
1215a2bb572a95
138032858b6c2
143b711467905
151db51cd93d8
hex10163d2b691

1105481348753 has 2 divisors, whose sum is σ = 1105481348754. Its totient is φ = 1105481348752.

The previous prime is 1105481348717. The next prime is 1105481348779. The reversal of 1105481348753 is 3578431845011.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1058579650129 + 46901698624 = 1028873^2 + 216568^2 .

It is a cyclic number.

It is not a de Polignac number, because 1105481348753 - 214 = 1105481332369 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is not a weakly prime, because it can be changed into another prime (1105481348953) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 552740674376 + 552740674377.

It is an arithmetic number, because the mean of its divisors is an integer number (552740674377).

Almost surely, 21105481348753 is an apocalyptic number.

It is an amenable number.

1105481348753 is a deficient number, since it is larger than the sum of its proper divisors (1).

1105481348753 is an equidigital number, since it uses as much as digits as its factorization.

1105481348753 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1612800, while the sum is 50.

The spelling of 1105481348753 in words is "one trillion, one hundred five billion, four hundred eighty-one million, three hundred forty-eight thousand, seven hundred fifty-three".