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1105516971457 is a prime number
BaseRepresentation
bin10000000101100101111…
…100100100010111000001
310220200112101012221210221
4100011211330210113001
5121103044321041312
62203511213223041
7142604512132303
oct20054574442701
93820471187727
101105516971457
11396935567338
1215a30b491a81
1380332a81a22
143b71609b973
151db54ec4207
hex10165f245c1

1105516971457 has 2 divisors, whose sum is σ = 1105516971458. Its totient is φ = 1105516971456.

The previous prime is 1105516971451. The next prime is 1105516971469. The reversal of 1105516971457 is 7541796155011.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1077410784256 + 28106187201 = 1037984^2 + 167649^2 .

It is a cyclic number.

It is not a de Polignac number, because 1105516971457 - 215 = 1105516938689 is a prime.

It is not a weakly prime, because it can be changed into another prime (1105516971451) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 552758485728 + 552758485729.

It is an arithmetic number, because the mean of its divisors is an integer number (552758485729).

Almost surely, 21105516971457 is an apocalyptic number.

It is an amenable number.

1105516971457 is a deficient number, since it is larger than the sum of its proper divisors (1).

1105516971457 is an equidigital number, since it uses as much as digits as its factorization.

1105516971457 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1323000, while the sum is 52.

The spelling of 1105516971457 in words is "one trillion, one hundred five billion, five hundred sixteen million, nine hundred seventy-one thousand, four hundred fifty-seven".