Base | Representation |
---|---|
bin | 1010000011101101010100… |
… | …0010111010101101110111 |
3 | 1110011012202012002222000211 |
4 | 2200323111002322231313 |
5 | 2422141430423203303 |
6 | 35304203555050251 |
7 | 2220654605100631 |
oct | 240732502725567 |
9 | 43135665088024 |
10 | 11058820131703 |
11 | 3584023730503 |
12 | 12a73345a0987 |
13 | 622ac45b8106 |
14 | 2a336d459a51 |
15 | 1429ea54b66d |
hex | a0ed50bab77 |
11058820131703 has 2 divisors, whose sum is σ = 11058820131704. Its totient is φ = 11058820131702.
The previous prime is 11058820131691. The next prime is 11058820131839. The reversal of 11058820131703 is 30713102885011.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11058820131703 - 225 = 11058786577271 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11058820141703) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5529410065851 + 5529410065852.
It is an arithmetic number, because the mean of its divisors is an integer number (5529410065852).
Almost surely, 211058820131703 is an apocalyptic number.
11058820131703 is a deficient number, since it is larger than the sum of its proper divisors (1).
11058820131703 is an equidigital number, since it uses as much as digits as its factorization.
11058820131703 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 40320, while the sum is 40.
The spelling of 11058820131703 in words is "eleven trillion, fifty-eight billion, eight hundred twenty million, one hundred thirty-one thousand, seven hundred three".
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