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110599421353 is a prime number
BaseRepresentation
bin110011100000000111…
…1010011110110101001
3101120110212022201212221
41213000033103312221
53303001422440403
6122450401234041
710663520366401
oct1470017236651
9346425281787
10110599421353
11429a5543263
1219527632921
13a5777522b5
1454d2a59801
152d24a4ddbd
hex19c03d3da9

110599421353 has 2 divisors, whose sum is σ = 110599421354. Its totient is φ = 110599421352.

The previous prime is 110599421329. The next prime is 110599421377. The reversal of 110599421353 is 353124995011.

It is a balanced prime because it is at equal distance from previous prime (110599421329) and next prime (110599421377).

It can be written as a sum of positive squares in only one way, i.e., 110598148969 + 1272384 = 332563^2 + 1128^2 .

It is a cyclic number.

It is not a de Polignac number, because 110599421353 - 225 = 110565866921 is a prime.

It is a super-3 number, since 3×1105994213533 (a number of 34 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (110599481353) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55299710676 + 55299710677.

It is an arithmetic number, because the mean of its divisors is an integer number (55299710677).

Almost surely, 2110599421353 is an apocalyptic number.

It is an amenable number.

110599421353 is a deficient number, since it is larger than the sum of its proper divisors (1).

110599421353 is an equidigital number, since it uses as much as digits as its factorization.

110599421353 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 145800, while the sum is 43.

The spelling of 110599421353 in words is "one hundred ten billion, five hundred ninety-nine million, four hundred twenty-one thousand, three hundred fifty-three".