Base | Representation |
---|---|
bin | 1010000011110101001110… |
… | …1000110101100100000111 |
3 | 1110011102020012112201101021 |
4 | 2200331103220311210013 |
5 | 2422210303131020122 |
6 | 35305154425012011 |
7 | 2221061334511345 |
oct | 240752350654407 |
9 | 43142205481337 |
10 | 11060944001287 |
11 | 3584a13592124 |
12 | 12a7827924007 |
13 | 62307261278b |
14 | 2a34d155a995 |
15 | 142ac1c2b1c7 |
hex | a0f53a35907 |
11060944001287 has 2 divisors, whose sum is σ = 11060944001288. Its totient is φ = 11060944001286.
The previous prime is 11060944001269. The next prime is 11060944001291. The reversal of 11060944001287 is 78210044906011.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11060944001287 - 235 = 11026584262919 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11060944001087) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5530472000643 + 5530472000644.
It is an arithmetic number, because the mean of its divisors is an integer number (5530472000644).
Almost surely, 211060944001287 is an apocalyptic number.
11060944001287 is a deficient number, since it is larger than the sum of its proper divisors (1).
11060944001287 is an equidigital number, since it uses as much as digits as its factorization.
11060944001287 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 96768, while the sum is 43.
Adding to 11060944001287 its reverse (78210044906011), we get a palindrome (89270988907298).
The spelling of 11060944001287 in words is "eleven trillion, sixty billion, nine hundred forty-four million, one thousand, two hundred eighty-seven".
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