Base | Representation |
---|---|
bin | 10100100110101010… |
… | …00011110011111111 |
3 | 1001112220112212221012 |
4 | 22103111003303333 |
5 | 140123244042413 |
6 | 5025350425435 |
7 | 541055643446 |
oct | 122325036377 |
9 | 31486485835 |
10 | 11061705983 |
11 | 4767054479 |
12 | 218866227b |
13 | 1073950c73 |
14 | 76d173d5d |
15 | 44b1cc7a8 |
hex | 293543cff |
11061705983 has 2 divisors, whose sum is σ = 11061705984. Its totient is φ = 11061705982.
The previous prime is 11061705961. The next prime is 11061706021. The reversal of 11061705983 is 38950716011.
It is a weak prime.
It is an emirp because it is prime and its reverse (38950716011) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 11061705983 - 230 = 9987964159 is a prime.
It is a super-2 number, since 2×110617059832 (a number of 21 digits) contains 22 as substring.
It is a Sophie Germain prime.
It is a self number, because there is not a number n which added to its sum of digits gives 11061705983.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11061755983) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5530852991 + 5530852992.
It is an arithmetic number, because the mean of its divisors is an integer number (5530852992).
Almost surely, 211061705983 is an apocalyptic number.
11061705983 is a deficient number, since it is larger than the sum of its proper divisors (1).
11061705983 is an equidigital number, since it uses as much as digits as its factorization.
11061705983 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 45360, while the sum is 41.
The spelling of 11061705983 in words is "eleven billion, sixty-one million, seven hundred five thousand, nine hundred eighty-three".
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