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11066049807353 is a prime number
BaseRepresentation
bin1010000100001000001111…
…1101111100001111111001
31110011220102001000112120122
42201002003331330033321
52422301232222313403
635311401220103025
72221332013242332
oct241020375741771
943156361015518
1011066049807353
1135870a3696862
1212a8811834a75
136236a73687b8
142a38576c1289
15142cc00d2838
hexa1083f7c3f9

11066049807353 has 2 divisors, whose sum is σ = 11066049807354. Its totient is φ = 11066049807352.

The previous prime is 11066049807341. The next prime is 11066049807409. The reversal of 11066049807353 is 35370894066011.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 11060393564089 + 5656243264 = 3325717^2 + 75208^2 .

It is a cyclic number.

It is not a de Polignac number, because 11066049807353 - 28 = 11066049807097 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 11066049807295 and 11066049807304.

It is not a weakly prime, because it can be changed into another prime (11066049107353) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5533024903676 + 5533024903677.

It is an arithmetic number, because the mean of its divisors is an integer number (5533024903677).

Almost surely, 211066049807353 is an apocalyptic number.

It is an amenable number.

11066049807353 is a deficient number, since it is larger than the sum of its proper divisors (1).

11066049807353 is an equidigital number, since it uses as much as digits as its factorization.

11066049807353 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3265920, while the sum is 53.

The spelling of 11066049807353 in words is "eleven trillion, sixty-six billion, forty-nine million, eight hundred seven thousand, three hundred fifty-three".