Base | Representation |
---|---|
bin | 10000000110110000101… |
… | …101000111110001011111 |
3 | 10220210202210022001022111 |
4 | 100012300231013301133 |
5 | 121113131412312112 |
6 | 2204235500054451 |
7 | 142650552043336 |
oct | 20066055076137 |
9 | 3823683261274 |
10 | 1106771213407 |
11 | 397419550932 |
12 | 15a5bb534427 |
13 | 804a2888322 |
14 | 3b7d48aad1d |
15 | 1dbca1765a7 |
hex | 101b0b47c5f |
1106771213407 has 2 divisors, whose sum is σ = 1106771213408. Its totient is φ = 1106771213406.
The previous prime is 1106771213393. The next prime is 1106771213419. The reversal of 1106771213407 is 7043121776011.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1106771213407 - 27 = 1106771213279 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 1106771213407.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1106771213467) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 553385606703 + 553385606704.
It is an arithmetic number, because the mean of its divisors is an integer number (553385606704).
Almost surely, 21106771213407 is an apocalyptic number.
1106771213407 is a deficient number, since it is larger than the sum of its proper divisors (1).
1106771213407 is an equidigital number, since it uses as much as digits as its factorization.
1106771213407 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 49392, while the sum is 40.
Adding to 1106771213407 its reverse (7043121776011), we get a palindrome (8149892989418).
The spelling of 1106771213407 in words is "one trillion, one hundred six billion, seven hundred seventy-one million, two hundred thirteen thousand, four hundred seven".
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