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110807993 is a prime number
BaseRepresentation
bin1101001101011…
…00101110111001
321201111121222202
412212230232321
5211331323433
614554555545
72513565242
oct646545671
9251447882
10110807993
115760375a
1231138bb5
1319c5907a
1410a05cc9
159adbee8
hex69acbb9

110807993 has 2 divisors, whose sum is σ = 110807994. Its totient is φ = 110807992.

The previous prime is 110807923. The next prime is 110808037. The reversal of 110807993 is 399708011.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 110607289 + 200704 = 10517^2 + 448^2 .

It is a cyclic number.

It is not a de Polignac number, because 110807993 - 28 = 110807737 is a prime.

It is a super-2 number, since 2×1108079932 = 24556822625376098, which contains 22 as substring.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (110807923) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55403996 + 55403997.

It is an arithmetic number, because the mean of its divisors is an integer number (55403997).

Almost surely, 2110807993 is an apocalyptic number.

It is an amenable number.

110807993 is a deficient number, since it is larger than the sum of its proper divisors (1).

110807993 is an equidigital number, since it uses as much as digits as its factorization.

110807993 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 13608, while the sum is 38.

The square root of 110807993 is about 10526.5375599007. The cubic root of 110807993 is about 480.3122866558.

The spelling of 110807993 in words is "one hundred ten million, eight hundred seven thousand, nine hundred ninety-three".