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11090131279933 is a prime number
BaseRepresentation
bin1010000101100001111101…
…0101011110000000111101
31110021012120022120002122111
42201120133111132000331
52423200042101424213
635330422545414021
72223143535341236
oct241303725360075
943235508502574
1011090131279933
113596330a96612
1212b141263a311
13625a444bc564
142a4a9da8808d
1514372e318a3d
hexa161f55e03d

11090131279933 has 2 divisors, whose sum is σ = 11090131279934. Its totient is φ = 11090131279932.

The previous prime is 11090131279853. The next prime is 11090131279939. The reversal of 11090131279933 is 33997213109011.

11090131279933 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 6213264140164 + 4876867139769 = 2492642^2 + 2208363^2 .

It is a cyclic number.

It is not a de Polignac number, because 11090131279933 - 217 = 11090131148861 is a prime.

It is a super-2 number, since 2×110901312799332 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11090131279939) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5545065639966 + 5545065639967.

It is an arithmetic number, because the mean of its divisors is an integer number (5545065639967).

Almost surely, 211090131279933 is an apocalyptic number.

It is an amenable number.

11090131279933 is a deficient number, since it is larger than the sum of its proper divisors (1).

11090131279933 is an equidigital number, since it uses as much as digits as its factorization.

11090131279933 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 275562, while the sum is 49.

The spelling of 11090131279933 in words is "eleven trillion, ninety billion, one hundred thirty-one million, two hundred seventy-nine thousand, nine hundred thirty-three".