Base | Representation |
---|---|
bin | 110011101011111101… |
… | …1001101110010010111 |
3 | 101121111120002000020201 |
4 | 1213113323031302113 |
5 | 3304310140304212 |
6 | 122554034441331 |
7 | 11006414201515 |
oct | 1472773156227 |
9 | 347446060221 |
10 | 110996806807 |
11 | 43089892897 |
12 | 19618733247 |
13 | a60bb89813 |
14 | 552d73d4b5 |
15 | 2d49897b57 |
hex | 19d7ecdc97 |
110996806807 has 2 divisors, whose sum is σ = 110996806808. Its totient is φ = 110996806806.
The previous prime is 110996806799. The next prime is 110996806859. The reversal of 110996806807 is 708608699011.
It is a weak prime.
It is an emirp because it is prime and its reverse (708608699011) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 110996806807 - 23 = 110996806799 is a prime.
It is a super-2 number, since 2×1109968068072 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (110996876807) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55498403403 + 55498403404.
It is an arithmetic number, because the mean of its divisors is an integer number (55498403404).
Almost surely, 2110996806807 is an apocalyptic number.
110996806807 is a deficient number, since it is larger than the sum of its proper divisors (1).
110996806807 is an equidigital number, since it uses as much as digits as its factorization.
110996806807 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1306368, while the sum is 55.
The spelling of 110996806807 in words is "one hundred ten billion, nine hundred ninety-six million, eight hundred six thousand, eight hundred seven".
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