11100010121113 has 2 divisors, whose sum is σ = 11100010121114. Its totient is φ = 11100010121112.

The previous prime is 11100010121111. The next prime is 11100010121131. The reversal of 11100010121113 is 31112101000111.

Together with next prime (11100010121131) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 10217919116304 + 882091004809 = 3196548^2 + 939197^2 .

It is a cyclic number.

It is not a de Polignac number, because 11100010121113 - 2¹ = 11100010121111 is a prime.

It is a super-2 number, since 2×11100010121113² (a number of 27 digits) contains 22 as substring.

Together with 11100010121111, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 11100010121093 and 11100010121102.

It is not a weakly prime, because it can be changed into another prime (11100010121111) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5550005060556 + 5550005060557.

It is an arithmetic number, because the mean of its divisors is an integer number (5550005060557).

Almost surely, 2^{11100010121113} is an apocalyptic number.

It is an amenable number.

11100010121113 is a deficient number, since it is larger than the sum of its proper divisors (1).

11100010121113 is an equidigital number, since it uses as much as digits as its factorization.

11100010121113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6, while the sum is 13.

Adding to 11100010121113 its reverse (31112101000111), we get a palindrome (42212111121224).

The spelling of 11100010121113 in words is "eleven trillion, one hundred billion, ten million, one hundred twenty-one thousand, one hundred thirteen".