Base | Representation |
---|---|
bin | 10000001001110001010… |
… | …110100110100110000111 |
3 | 10221010010001001201110222 |
4 | 100021301112212212013 |
5 | 121141241322004111 |
6 | 2205532315134555 |
7 | 143123626325324 |
oct | 20116126464607 |
9 | 3833101051428 |
10 | 1110003313031 |
11 | 398827a29148 |
12 | 15b161a4445b |
13 | 80899385702 |
14 | 3ba1dc4db4b |
15 | 1dd18cb57db |
hex | 102715a6987 |
1110003313031 has 2 divisors, whose sum is σ = 1110003313032. Its totient is φ = 1110003313030.
The previous prime is 1110003312991. The next prime is 1110003313037. The reversal of 1110003313031 is 1303133000111.
It is a strong prime.
It is an emirp because it is prime and its reverse (1303133000111) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1110003313031 is a prime.
It is a super-2 number, since 2×11100033130312 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1110003313037) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 555001656515 + 555001656516.
It is an arithmetic number, because the mean of its divisors is an integer number (555001656516).
Almost surely, 21110003313031 is an apocalyptic number.
1110003313031 is a deficient number, since it is larger than the sum of its proper divisors (1).
1110003313031 is an equidigital number, since it uses as much as digits as its factorization.
1110003313031 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 81, while the sum is 17.
Adding to 1110003313031 its reverse (1303133000111), we get a palindrome (2413136313142).
The spelling of 1110003313031 in words is "one trillion, one hundred ten billion, three million, three hundred thirteen thousand, thirty-one".
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