Base | Representation |
---|---|
bin | 1010000110000111000110… |
… | …0001000111100100000111 |
3 | 1110022011022001110112210002 |
4 | 2201201301201013210013 |
5 | 2423331001100000012 |
6 | 35335152053551515 |
7 | 2223645553144124 |
oct | 241416141074407 |
9 | 43264261415702 |
10 | 11100100000007 |
11 | 359a587086547 |
12 | 12b333504559b |
13 | 6269728772a5 |
14 | 2a53679c774b |
15 | 143b145987c2 |
hex | a1871847907 |
11100100000007 has 2 divisors, whose sum is σ = 11100100000008. Its totient is φ = 11100100000006.
The previous prime is 11100099999953. The next prime is 11100100000019. The reversal of 11100100000007 is 70000000100111.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11100100000007 - 210 = 11100099998983 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11100100002007) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5550050000003 + 5550050000004.
It is an arithmetic number, because the mean of its divisors is an integer number (5550050000004).
Almost surely, 211100100000007 is an apocalyptic number.
11100100000007 is a deficient number, since it is larger than the sum of its proper divisors (1).
11100100000007 is an equidigital number, since it uses as much as digits as its factorization.
11100100000007 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 7, while the sum is 11.
Adding to 11100100000007 its reverse (70000000100111), we get a palindrome (81100100100118).
The spelling of 11100100000007 in words is "eleven trillion, one hundred billion, one hundred million, seven", and thus it is an aban number.
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