111001001011213 has 2 divisors, whose sum is σ = 111001001011214. Its totient is φ = 111001001011212.

The previous prime is 111001001011207. The next prime is 111001001011231. The reversal of 111001001011213 is 312110100100111.

Together with next prime (111001001011231) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 109256282320329 + 1744718690884 = 10452573^2 + 1320878^2 .

It is a cyclic number.

It is not a de Polignac number, because 111001001011213 - 2¹³ = 111001001003021 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 111001001011193 and 111001001011202.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (111001001011013) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55500500505606 + 55500500505607.

It is an arithmetic number, because the mean of its divisors is an integer number (55500500505607).

Almost surely, 2^{111001001011213} is an apocalyptic number.

It is an amenable number.

111001001011213 is a deficient number, since it is larger than the sum of its proper divisors (1).

111001001011213 is an equidigital number, since it uses as much as digits as its factorization.

111001001011213 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6, while the sum is 13.

Adding to 111001001011213 its reverse (312110100100111), we get a palindrome (423111101111324).

The spelling of 111001001011213 in words is "one hundred eleven trillion, one billion, one million, eleven thousand, two hundred thirteen".