Base | Representation |
---|---|
bin | 10000001001110001110… |
… | …000011111100100001101 |
3 | 10221010010111211112102111 |
4 | 100021301300133210031 |
5 | 121141300041144411 |
6 | 2205533120424021 |
7 | 143124041113336 |
oct | 20116160374415 |
9 | 3833114745374 |
10 | 1110010099981 |
11 | 3988308442a2 |
12 | 15b164178011 |
13 | 8089a8c0963 |
14 | 3ba20ad928d |
15 | 1dd196a6721 |
hex | 10271c1f90d |
1110010099981 has 2 divisors, whose sum is σ = 1110010099982. Its totient is φ = 1110010099980.
The previous prime is 1110010099969. The next prime is 1110010100027. The reversal of 1110010099981 is 1899900100111.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1107440522500 + 2569577481 = 1052350^2 + 50691^2 .
It is a cyclic number.
It is not a de Polignac number, because 1110010099981 - 25 = 1110010099949 is a prime.
It is a super-2 number, since 2×11100100999812 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1110010099931) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 555005049990 + 555005049991.
It is an arithmetic number, because the mean of its divisors is an integer number (555005049991).
Almost surely, 21110010099981 is an apocalyptic number.
It is an amenable number.
1110010099981 is a deficient number, since it is larger than the sum of its proper divisors (1).
1110010099981 is an equidigital number, since it uses as much as digits as its factorization.
1110010099981 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5832, while the sum is 40.
The spelling of 1110010099981 in words is "one trillion, one hundred ten billion, ten million, ninety-nine thousand, nine hundred eighty-one".
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