Search a number
-
+
11100102113 is a prime number
BaseRepresentation
bin10100101011001111…
…00001110111100001
31001122120210121112002
422111213201313201
5140213111231423
65033241413345
7542033211512
oct122547416741
931576717462
1011100102113
11478679a011
12219949a255
13107b8a5779
147742caa09
1544e764228
hex2959e1de1

11100102113 has 2 divisors, whose sum is σ = 11100102114. Its totient is φ = 11100102112.

The previous prime is 11100102071. The next prime is 11100102127. The reversal of 11100102113 is 31120100111.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9688071184 + 1412030929 = 98428^2 + 37577^2 .

It is a cyclic number.

It is not a de Polignac number, because 11100102113 - 212 = 11100098017 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 11100102094 and 11100102103.

It is not a weakly prime, because it can be changed into another prime (11100102313) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5550051056 + 5550051057.

It is an arithmetic number, because the mean of its divisors is an integer number (5550051057).

Almost surely, 211100102113 is an apocalyptic number.

It is an amenable number.

11100102113 is a deficient number, since it is larger than the sum of its proper divisors (1).

11100102113 is an equidigital number, since it uses as much as digits as its factorization.

11100102113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6, while the sum is 11.

Adding to 11100102113 its reverse (31120100111), we get a palindrome (42220202224).

The spelling of 11100102113 in words is "eleven billion, one hundred million, one hundred two thousand, one hundred thirteen".