11100110083 has 2 divisors, whose sum is σ = 11100110084. Its totient is φ = 11100110082.

The previous prime is 11100110069. The next prime is 11100110183. The reversal of 11100110083 is 38001100111.

11100110083 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 11100110083 - 2²¹ = 11098012931 is a prime.

It is not a weakly prime, because it can be changed into another prime (11100110053) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5550055041 + 5550055042.

It is an arithmetic number, because the mean of its divisors is an integer number (5550055042).

Almost surely, 2^11100110083 is an apocalyptic number.

11100110083 is a deficient number, since it is larger than the sum of its proper divisors (1).

11100110083 is an equidigital number, since it uses as much as digits as its factorization.

11100110083 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 24, while the sum is 16.

Adding to 11100110083 its reverse (38001100111), we get a palindrome (49101210194).

The spelling of 11100110083 in words is "eleven billion, one hundred million, one hundred ten thousand, eighty-three".