1110011330213 has 2 divisors, whose sum is σ = 1110011330214. Its totient is φ = 1110011330212.

The previous prime is 1110011330201. The next prime is 1110011330237. The reversal of 1110011330213 is 3120331100111.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1070018529889 + 39992800324 = 1034417^2 + 199982^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1110011330213 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1110011330191 and 1110011330200.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1110011330413) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 555005665106 + 555005665107.

It is an arithmetic number, because the mean of its divisors is an integer number (555005665107).

Almost surely, 2^{1110011330213} is an apocalyptic number.

It is an amenable number.

1110011330213 is a deficient number, since it is larger than the sum of its proper divisors (1).

1110011330213 is an equidigital number, since it uses as much as digits as its factorization.

1110011330213 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 54, while the sum is 17.

Adding to 1110011330213 its reverse (3120331100111), we get a palindrome (4230342430324).

The spelling of 1110011330213 in words is "one trillion, one hundred ten billion, eleven million, three hundred thirty thousand, two hundred thirteen".