11100120113 has 2 divisors, whose sum is σ = 11100120114. Its totient is φ = 11100120112.

The previous prime is 11100120107. The next prime is 11100120151. The reversal of 11100120113 is 31102100111.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 7668855184 + 3431264929 = 87572^2 + 58577^2 .

It is a cyclic number.

It is not a de Polignac number, because 11100120113 - 2²² = 11095925809 is a prime.

It is a super-4 number, since 4×11100120113⁴ (a number of 41 digits) contains 4444 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 11100120094 and 11100120103.

It is not a weakly prime, because it can be changed into another prime (11100120013) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5550060056 + 5550060057.

It is an arithmetic number, because the mean of its divisors is an integer number (5550060057).

Almost surely, 2^11100120113 is an apocalyptic number.

It is an amenable number.

11100120113 is a deficient number, since it is larger than the sum of its proper divisors (1).

11100120113 is an equidigital number, since it uses as much as digits as its factorization.

11100120113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6, while the sum is 11.

Adding to 11100120113 its reverse (31102100111), we get a palindrome (42202220224).

The spelling of 11100120113 in words is "eleven billion, one hundred million, one hundred twenty thousand, one hundred thirteen".