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11100130121981 is a prime number
BaseRepresentation
bin1010000110000111001101…
…0100000001100011111101
31110022011101011010220100202
42201201303110001203331
52423331031302400411
635335155051333245
72223646400161235
oct241416324014375
943264334126322
1011100130121981
11359a5a208a63a
1212b3343151225
13626978b92944
142a536b9c8cc5
15143b1704883b
hexa18735018fd

11100130121981 has 2 divisors, whose sum is σ = 11100130121982. Its totient is φ = 11100130121980.

The previous prime is 11100130121911. The next prime is 11100130122049. The reversal of 11100130121981 is 18912103100111.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9306831504100 + 1793298617881 = 3050710^2 + 1339141^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11100130121981 is a prime.

It is a super-2 number, since 2×111001301219812 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11100130121911) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5550065060990 + 5550065060991.

It is an arithmetic number, because the mean of its divisors is an integer number (5550065060991).

Almost surely, 211100130121981 is an apocalyptic number.

It is an amenable number.

11100130121981 is a deficient number, since it is larger than the sum of its proper divisors (1).

11100130121981 is an equidigital number, since it uses as much as digits as its factorization.

11100130121981 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 432, while the sum is 29.

The spelling of 11100130121981 in words is "eleven trillion, one hundred billion, one hundred thirty million, one hundred twenty-one thousand, nine hundred eighty-one".