Base | Representation |
---|---|
bin | 110011101100000110… |
… | …0011001110000111001 |
3 | 101121111212112220122022 |
4 | 1213120030121300321 |
5 | 3304312313443223 |
6 | 122554315204225 |
7 | 11006500405223 |
oct | 1473014316071 |
9 | 347455486568 |
10 | 111001312313 |
11 | 4309138a951 |
12 | 1961a146675 |
13 | a60caa64b8 |
14 | 5530193413 |
15 | 2d49e87ac8 |
hex | 19d8319c39 |
111001312313 has 2 divisors, whose sum is σ = 111001312314. Its totient is φ = 111001312312.
The previous prime is 111001312307. The next prime is 111001312319. The reversal of 111001312313 is 313213100111.
It is a balanced prime because it is at equal distance from previous prime (111001312307) and next prime (111001312319).
It can be written as a sum of positive squares in only one way, i.e., 110468487424 + 532824889 = 332368^2 + 23083^2 .
It is a cyclic number.
It is not a de Polignac number, because 111001312313 - 212 = 111001308217 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 111001312291 and 111001312300.
It is not a weakly prime, because it can be changed into another prime (111001312319) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55500656156 + 55500656157.
It is an arithmetic number, because the mean of its divisors is an integer number (55500656157).
Almost surely, 2111001312313 is an apocalyptic number.
It is an amenable number.
111001312313 is a deficient number, since it is larger than the sum of its proper divisors (1).
111001312313 is an equidigital number, since it uses as much as digits as its factorization.
111001312313 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 54, while the sum is 17.
Adding to 111001312313 its reverse (313213100111), we get a palindrome (424214412424).
The spelling of 111001312313 in words is "one hundred eleven billion, one million, three hundred twelve thousand, three hundred thirteen".
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