Base | Representation |
---|---|
bin | 11001001111010010001001… |
… | …000011111100110101111011 |
3 | 112120000122002210212210211222 |
4 | 121033102021003330311323 |
5 | 104022121414140441214 |
6 | 1032025204400342255 |
7 | 32244406006646444 |
oct | 3117221103746573 |
9 | 476018083783758 |
10 | 111001434312059 |
11 | 3240649795aa55 |
12 | 105489a391498b |
13 | 49c250c770355 |
14 | 1d5a6d8a6c2cb |
15 | cc7606d4a38e |
hex | 64f4890fcd7b |
111001434312059 has 2 divisors, whose sum is σ = 111001434312060. Its totient is φ = 111001434312058.
The previous prime is 111001434312037. The next prime is 111001434312061. The reversal of 111001434312059 is 950213434100111.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 111001434312059 - 236 = 110932714835323 is a prime.
Together with 111001434312061, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (111001434312959) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55500717156029 + 55500717156030.
It is an arithmetic number, because the mean of its divisors is an integer number (55500717156030).
Almost surely, 2111001434312059 is an apocalyptic number.
111001434312059 is a deficient number, since it is larger than the sum of its proper divisors (1).
111001434312059 is an equidigital number, since it uses as much as digits as its factorization.
111001434312059 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 12960, while the sum is 35.
The spelling of 111001434312059 in words is "one hundred eleven trillion, one billion, four hundred thirty-four million, three hundred twelve thousand, fifty-nine".
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