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111001434312143 is a prime number
BaseRepresentation
bin11001001111010010001001…
…000011111100110111001111
3112120000122002210212210222002
4121033102021003330313033
5104022121414140442033
61032025204400342515
732244406006646624
oct3117221103746717
9476018083783862
10111001434312143
1132406497960021
12105489a3914a3b
1349c250c7703bb
141d5a6d8a6c34b
15cc7606d4a3e8
hex64f4890fcdcf

111001434312143 has 2 divisors, whose sum is σ = 111001434312144. Its totient is φ = 111001434312142.

The previous prime is 111001434312077. The next prime is 111001434312157. The reversal of 111001434312143 is 341213434100111.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-111001434312143 is a prime.

It is a Sophie Germain prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (111001434312343) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55500717156071 + 55500717156072.

It is an arithmetic number, because the mean of its divisors is an integer number (55500717156072).

Almost surely, 2111001434312143 is an apocalyptic number.

111001434312143 is a deficient number, since it is larger than the sum of its proper divisors (1).

111001434312143 is an equidigital number, since it uses as much as digits as its factorization.

111001434312143 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3456, while the sum is 29.

Adding to 111001434312143 its reverse (341213434100111), we get a palindrome (452214868412254).

The spelling of 111001434312143 in words is "one hundred eleven trillion, one billion, four hundred thirty-four million, three hundred twelve thousand, one hundred forty-three".