Base | Representation |
---|---|
bin | 11001001111010010110001… |
… | …010101100010101011110011 |
3 | 112120000200211220022221010011 |
4 | 121033102301111202223303 |
5 | 104022124310130342042 |
6 | 1032025355415115351 |
7 | 32244431523212524 |
oct | 3117226125425363 |
9 | 476020756287104 |
10 | 111002110012147 |
11 | 32406804312482 |
12 | 10548b52072b57 |
13 | 49c25b97520a3 |
14 | 1d5a7606bc84b |
15 | cc764631ca17 |
hex | 64f4b1562af3 |
111002110012147 has 2 divisors, whose sum is σ = 111002110012148. Its totient is φ = 111002110012146.
The previous prime is 111002110012081. The next prime is 111002110012181. The reversal of 111002110012147 is 741210011200111.
It is a strong prime.
It is an emirp because it is prime and its reverse (741210011200111) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 111002110012147 - 27 = 111002110012019 is a prime.
It is not a weakly prime, because it can be changed into another prime (111002110052147) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55501055006073 + 55501055006074.
It is an arithmetic number, because the mean of its divisors is an integer number (55501055006074).
Almost surely, 2111002110012147 is an apocalyptic number.
111002110012147 is a deficient number, since it is larger than the sum of its proper divisors (1).
111002110012147 is an equidigital number, since it uses as much as digits as its factorization.
111002110012147 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 112, while the sum is 22.
Adding to 111002110012147 its reverse (741210011200111), we get a palindrome (852212121212258).
The spelling of 111002110012147 in words is "one hundred eleven trillion, two billion, one hundred ten million, twelve thousand, one hundred forty-seven".
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