Base | Representation |
---|---|
bin | 110011101100000111… |
… | …1011100110010101011 |
3 | 101121111221001111102202 |
4 | 1213120033130302223 |
5 | 3304313020024042 |
6 | 122554344250415 |
7 | 11006510243204 |
oct | 1473017346253 |
9 | 347457044382 |
10 | 111002111147 |
11 | 43091886044 |
12 | 1961a470a0b |
13 | a60ccc5c95 |
14 | 55303205ab |
15 | 2d4a094632 |
hex | 19d83dccab |
111002111147 has 2 divisors, whose sum is σ = 111002111148. Its totient is φ = 111002111146.
The previous prime is 111002111113. The next prime is 111002111149. The reversal of 111002111147 is 741111200111.
It is a strong prime.
It is an emirp because it is prime and its reverse (741111200111) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 111002111147 - 218 = 111001849003 is a prime.
Together with 111002111149, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (111002111149) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55501055573 + 55501055574.
It is an arithmetic number, because the mean of its divisors is an integer number (55501055574).
Almost surely, 2111002111147 is an apocalyptic number.
111002111147 is a deficient number, since it is larger than the sum of its proper divisors (1).
111002111147 is an equidigital number, since it uses as much as digits as its factorization.
111002111147 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 56, while the sum is 20.
Adding to 111002111147 its reverse (741111200111), we get a palindrome (852113311258).
The spelling of 111002111147 in words is "one hundred eleven billion, two million, one hundred eleven thousand, one hundred forty-seven".
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