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111003095041 is a prime number
BaseRepresentation
bin110011101100001001…
…1001101000000000001
3101121111222220111002021
41213120103031000001
53304313243020131
6122554421321441
711006521511536
oct1473023150001
9347458814067
10111003095041
1143092398283
121961a866281
13a61027ba77
1455304d8d8d
152d4a1dae11
hex19d84cd001

111003095041 has 2 divisors, whose sum is σ = 111003095042. Its totient is φ = 111003095040.

The previous prime is 111003095033. The next prime is 111003095053. The reversal of 111003095041 is 140590300111.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 109244131441 + 1758963600 = 330521^2 + 41940^2 .

It is an emirp because it is prime and its reverse (140590300111) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 111003095041 - 23 = 111003095033 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 111003094997 and 111003095015.

It is not a weakly prime, because it can be changed into another prime (111003095011) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55501547520 + 55501547521.

It is an arithmetic number, because the mean of its divisors is an integer number (55501547521).

Almost surely, 2111003095041 is an apocalyptic number.

It is an amenable number.

111003095041 is a deficient number, since it is larger than the sum of its proper divisors (1).

111003095041 is an equidigital number, since it uses as much as digits as its factorization.

111003095041 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 540, while the sum is 25.

Adding to 111003095041 its reverse (140590300111), we get a palindrome (251593395152).

The spelling of 111003095041 in words is "one hundred eleven billion, three million, ninety-five thousand, forty-one".