Base | Representation |
---|---|
bin | 11001001111010011111001… |
… | …000011000000001111010111 |
3 | 112120000210221202011201212211 |
4 | 121033103321003000033113 |
5 | 104022134241124041043 |
6 | 1032030115033454251 |
7 | 32244503402331403 |
oct | 3117237103001727 |
9 | 476023852151784 |
10 | 111003313112023 |
11 | 324072714461a2 |
12 | 10549228b71387 |
13 | 49c274ba904c7 |
14 | 1d5a8363b8103 |
15 | cc76b6c6ba9d |
hex | 64f4f90c03d7 |
111003313112023 has 2 divisors, whose sum is σ = 111003313112024. Its totient is φ = 111003313112022.
The previous prime is 111003313111967. The next prime is 111003313112051. The reversal of 111003313112023 is 320211313300111.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-111003313112023 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 111003313111985 and 111003313112003.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (111003313118023) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55501656556011 + 55501656556012.
It is an arithmetic number, because the mean of its divisors is an integer number (55501656556012).
Almost surely, 2111003313112023 is an apocalyptic number.
111003313112023 is a deficient number, since it is larger than the sum of its proper divisors (1).
111003313112023 is an equidigital number, since it uses as much as digits as its factorization.
111003313112023 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 324, while the sum is 22.
Adding to 111003313112023 its reverse (320211313300111), we get a palindrome (431214626412134).
The spelling of 111003313112023 in words is "one hundred eleven trillion, three billion, three hundred thirteen million, one hundred twelve thousand, twenty-three".
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