Search a number
-
+
11100401023 = 438914511999
BaseRepresentation
bin10100101011010001…
…01010110101111111
31001122121100210112211
422111220222311333
5140213200313043
65033252041251
7542035565125
oct122550526577
931577323484
1011100401023
114786983648
122199603227
13107b97b83a
14774367915
1544e7c2a9d
hex295a2ad7f

11100401023 has 16 divisors (see below), whose sum is σ = 11499840000. Its totient is φ = 10707681600.

The previous prime is 11100400999. The next prime is 11100401029. The reversal of 11100401023 is 32010400111.

It is a cyclic number.

It is not a de Polignac number, because 11100401023 - 25 = 11100400991 is a prime.

It is a super-3 number, since 3×111004010233 (a number of 31 digits) contains 333 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11100400994 and 11100401012.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11100401029) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 5551978 + ... + 5553976.

It is an arithmetic number, because the mean of its divisors is an integer number (718740000).

Almost surely, 211100401023 is an apocalyptic number.

11100401023 is a deficient number, since it is larger than the sum of its proper divisors (399438977).

11100401023 is a wasteful number, since it uses less digits than its factorization.

11100401023 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3582.

The product of its (nonzero) digits is 24, while the sum is 13.

Adding to 11100401023 its reverse (32010400111), we get a palindrome (43110801134).

The spelling of 11100401023 in words is "eleven billion, one hundred million, four hundred one thousand, twenty-three".

Divisors: 1 43 89 1451 1999 3827 62393 85957 129139 177911 2900549 5552977 7650173 124723607 258148861 11100401023