Base | Representation |
---|---|
bin | 10000001001110100101… |
… | …111000011101110111011 |
3 | 10221010020222211112111021 |
4 | 100021310233003232323 |
5 | 121141400333233413 |
6 | 2205542103243311 |
7 | 143125215534241 |
oct | 20116457035673 |
9 | 3833228745437 |
10 | 1110060055483 |
11 | 398856a64635 |
12 | 15b178a49537 |
13 | 808a8061a22 |
14 | 3ba275c0791 |
15 | 1dd1dc7318d |
hex | 10274bc3bbb |
1110060055483 has 2 divisors, whose sum is σ = 1110060055484. Its totient is φ = 1110060055482.
The previous prime is 1110060055451. The next prime is 1110060055561. The reversal of 1110060055483 is 3845500600111.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1110060055483 - 25 = 1110060055451 is a prime.
It is not a weakly prime, because it can be changed into another prime (1110060050483) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 555030027741 + 555030027742.
It is an arithmetic number, because the mean of its divisors is an integer number (555030027742).
Almost surely, 21110060055483 is an apocalyptic number.
1110060055483 is a deficient number, since it is larger than the sum of its proper divisors (1).
1110060055483 is an equidigital number, since it uses as much as digits as its factorization.
1110060055483 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 14400, while the sum is 34.
Adding to 1110060055483 its reverse (3845500600111), we get a palindrome (4955560655594).
The spelling of 1110060055483 in words is "one trillion, one hundred ten billion, sixty million, fifty-five thousand, four hundred eighty-three".
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