11101000993 has 2 divisors, whose sum is σ = 11101000994. Its totient is φ = 11101000992.

The previous prime is 11101000987. The next prime is 11101001029. The reversal of 11101000993 is 39900010111.

11101000993 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 9236747664 + 1864253329 = 96108^2 + 43177^2 .

It is a cyclic number.

It is not a de Polignac number, because 11101000993 - 2¹⁷ = 11100869921 is a prime.

It is a super-4 number, since 4×11101000993⁴ (a number of 41 digits) contains 4444 as substring.

It is not a weakly prime, because it can be changed into another prime (11101000693) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5550500496 + 5550500497.

It is an arithmetic number, because the mean of its divisors is an integer number (5550500497).

Almost surely, 2^11101000993 is an apocalyptic number.

It is an amenable number.

11101000993 is a deficient number, since it is larger than the sum of its proper divisors (1).

11101000993 is an equidigital number, since it uses as much as digits as its factorization.

11101000993 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 243, while the sum is 25.

The spelling of 11101000993 in words is "eleven billion, one hundred one million, nine hundred ninety-three", and thus it is an aban number.