Base | Representation |
---|---|
bin | 10000001001110111000… |
… | …111111100010011111001 |
3 | 10221010100210020200122221 |
4 | 100021313013330103321 |
5 | 121141441113224423 |
6 | 2205550054244041 |
7 | 143126213304526 |
oct | 20116707742371 |
9 | 3833323220587 |
10 | 1110100133113 |
11 | 398877648544 |
12 | 15b18a356621 |
13 | 808b34549ba |
14 | 3ba2ca5414d |
15 | 1dd2253ce5d |
hex | 102771fc4f9 |
1110100133113 has 2 divisors, whose sum is σ = 1110100133114. Its totient is φ = 1110100133112.
The previous prime is 1110100133111. The next prime is 1110100133159. The reversal of 1110100133113 is 3113310010111.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 589266563769 + 520833569344 = 767637^2 + 721688^2 .
It is a cyclic number.
It is not a de Polignac number, because 1110100133113 - 21 = 1110100133111 is a prime.
Together with 1110100133111, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (1110100133111) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 555050066556 + 555050066557.
It is an arithmetic number, because the mean of its divisors is an integer number (555050066557).
Almost surely, 21110100133113 is an apocalyptic number.
It is an amenable number.
1110100133113 is a deficient number, since it is larger than the sum of its proper divisors (1).
1110100133113 is an equidigital number, since it uses as much as digits as its factorization.
1110100133113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 27, while the sum is 16.
Adding to 1110100133113 its reverse (3113310010111), we get a palindrome (4223410143224).
The spelling of 1110100133113 in words is "one trillion, one hundred ten billion, one hundred million, one hundred thirty-three thousand, one hundred thirteen".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.066 sec. • engine limits •