Base | Representation |
---|---|
bin | 1010000110001010011111… |
… | …0000110111111110100101 |
3 | 1110022020122110222102110011 |
4 | 2201202213300313332211 |
5 | 2423334332041201013 |
6 | 35335422244330221 |
7 | 2224010243650222 |
oct | 241424760677645 |
9 | 43266573872404 |
10 | 11101010100133 |
11 | 359aa03887208 |
12 | 12b35499a3971 |
13 | 626a89298c85 |
14 | 2a5412812949 |
15 | 143b6941cc3d |
hex | a18a7c37fa5 |
11101010100133 has 2 divisors, whose sum is σ = 11101010100134. Its totient is φ = 11101010100132.
The previous prime is 11101010100109. The next prime is 11101010100137. The reversal of 11101010100133 is 33100101010111.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 7373820768484 + 3727189331649 = 2715478^2 + 1930593^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11101010100133 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11101010100137) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5550505050066 + 5550505050067.
It is an arithmetic number, because the mean of its divisors is an integer number (5550505050067).
Almost surely, 211101010100133 is an apocalyptic number.
It is an amenable number.
11101010100133 is a deficient number, since it is larger than the sum of its proper divisors (1).
11101010100133 is an equidigital number, since it uses as much as digits as its factorization.
11101010100133 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 9, while the sum is 13.
Adding to 11101010100133 its reverse (33100101010111), we get a palindrome (44201111110244).
The spelling of 11101010100133 in words is "eleven trillion, one hundred one billion, ten million, one hundred thousand, one hundred thirty-three".
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