111010111100113 has 2 divisors, whose sum is σ = 111010111100114. Its totient is φ = 111010111100112.

The previous prime is 111010111100093. The next prime is 111010111100159. The reversal of 111010111100113 is 311001111010111.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 108912746760129 + 2097364339984 = 10436127^2 + 1448228^2 .

It is a cyclic number.

It is not a de Polignac number, because 111010111100113 - 2⁵ = 111010111100081 is a prime.

It is a super-4 number, since 4×111010111100113⁴ (a number of 57 digits) contains 4444 as substring. Note that it is a super-d number also for d = 2.

It is a junction number, because it is equal to n+sod(n) for n = 111010111100093 and 111010111100102.

It is not a weakly prime, because it can be changed into another prime (111010111100183) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55505055550056 + 55505055550057.

It is an arithmetic number, because the mean of its divisors is an integer number (55505055550057).

Almost surely, 2^{111010111100113} is an apocalyptic number.

It is an amenable number.

111010111100113 is a deficient number, since it is larger than the sum of its proper divisors (1).

111010111100113 is an equidigital number, since it uses as much as digits as its factorization.

111010111100113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3, while the sum is 13.

Adding to 111010111100113 its reverse (311001111010111), we get a palindrome (422011222110224).

The spelling of 111010111100113 in words is "one hundred eleven trillion, ten billion, one hundred eleven million, one hundred thousand, one hundred thirteen".