11101012211281 has 2 divisors, whose sum is σ = 11101012211282. Its totient is φ = 11101012211280.

The previous prime is 11101012211269. The next prime is 11101012211327. The reversal of 11101012211281 is 18211221010111.

11101012211281 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 10564346080656 + 536666130625 = 3250284^2 + 732575^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-11101012211281 is a prime.

It is a super-3 number, since 3×11101012211281³ (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is not a weakly prime, because it can be changed into another prime (11101012218281) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5550506105640 + 5550506105641.

It is an arithmetic number, because the mean of its divisors is an integer number (5550506105641).

Almost surely, 2^{11101012211281} is an apocalyptic number.

It is an amenable number.

11101012211281 is a deficient number, since it is larger than the sum of its proper divisors (1).

11101012211281 is an equidigital number, since it uses as much as digits as its factorization.

11101012211281 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 64, while the sum is 22.

Adding to 11101012211281 its reverse (18211221010111), we get a palindrome (29312233221392).

The spelling of 11101012211281 in words is "eleven trillion, one hundred one billion, twelve million, two hundred eleven thousand, two hundred eighty-one".