Base | Representation |
---|---|
bin | 1010000110001010011111… |
… | …1100101111100011001101 |
3 | 1110022020122200211111020002 |
4 | 2201202213330233203031 |
5 | 2423334333340230331 |
6 | 35335422435134045 |
7 | 2224010312255624 |
oct | 241424774574315 |
9 | 43266580744202 |
10 | 11101013211341 |
11 | 359aa05611759 |
12 | 12b354aa44325 |
13 | 626a89b18121 |
14 | 2a5412dc26bb |
15 | 143b698349cb |
hex | a18a7f2f8cd |
11101013211341 has 2 divisors, whose sum is σ = 11101013211342. Its totient is φ = 11101013211340.
The previous prime is 11101013211289. The next prime is 11101013211401. The reversal of 11101013211341 is 14311231010111.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 6310294720900 + 4790718490441 = 2512030^2 + 2188771^2 .
It is a cyclic number.
It is not a de Polignac number, because 11101013211341 - 210 = 11101013210317 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11101013211241) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5550506605670 + 5550506605671.
It is an arithmetic number, because the mean of its divisors is an integer number (5550506605671).
Almost surely, 211101013211341 is an apocalyptic number.
It is an amenable number.
11101013211341 is a deficient number, since it is larger than the sum of its proper divisors (1).
11101013211341 is an equidigital number, since it uses as much as digits as its factorization.
11101013211341 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 72, while the sum is 20.
Adding to 11101013211341 its reverse (14311231010111), we get a palindrome (25412244221452).
The spelling of 11101013211341 in words is "eleven trillion, one hundred one billion, thirteen million, two hundred eleven thousand, three hundred forty-one".
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