Base | Representation |
---|---|
bin | 10000001001110111010… |
… | …100000001100011101011 |
3 | 10221010101000012121021022 |
4 | 100021313110001203223 |
5 | 121141442421102311 |
6 | 2205550250203055 |
7 | 143126252235434 |
oct | 20116724014353 |
9 | 3833330177238 |
10 | 1110103300331 |
11 | 398879411083 |
12 | 15b18b42348b |
13 | 808b3cc34ac |
14 | 3ba2d23a48b |
15 | 1dd229665db |
hex | 102775018eb |
1110103300331 has 2 divisors, whose sum is σ = 1110103300332. Its totient is φ = 1110103300330.
The previous prime is 1110103300289. The next prime is 1110103300333. The reversal of 1110103300331 is 1330033010111.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1110103300331 - 222 = 1110099106027 is a prime.
It is a super-2 number, since 2×11101033003312 (a number of 25 digits) contains 22 as substring.
It is a Sophie Germain prime.
Together with 1110103300333, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (1110103300333) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 555051650165 + 555051650166.
It is an arithmetic number, because the mean of its divisors is an integer number (555051650166).
Almost surely, 21110103300331 is an apocalyptic number.
1110103300331 is a deficient number, since it is larger than the sum of its proper divisors (1).
1110103300331 is an equidigital number, since it uses as much as digits as its factorization.
1110103300331 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 81, while the sum is 17.
Adding to 1110103300331 its reverse (1330033010111), we get a palindrome (2440136310442).
The spelling of 1110103300331 in words is "one trillion, one hundred ten billion, one hundred three million, three hundred thousand, three hundred thirty-one".
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