Base | Representation |
---|---|
bin | 110011101100010111… |
… | …1001110111101111100 |
3 | 101121112111201210202210 |
4 | 1213120233032331330 |
5 | 3304322133140012 |
6 | 122555243020420 |
7 | 11006641124541 |
oct | 1473057167574 |
9 | 347474653683 |
10 | 111010443132 |
11 | 43096556a86 |
12 | 1962120a710 |
13 | a611952554 |
14 | 553148cbc8 |
15 | 2d4ab8d23c |
hex | 19d8bcef7c |
111010443132 has 12 divisors (see below), whose sum is σ = 259024367336. Its totient is φ = 37003481040.
The previous prime is 111010443127. The next prime is 111010443133. The reversal of 111010443132 is 231344010111.
It is a tau number, because it is divible by the number of its divisors (12).
It is a junction number, because it is equal to n+sod(n) for n = 111010443099 and 111010443108.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (111010443133) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4625435119 + ... + 4625435142.
Almost surely, 2111010443132 is an apocalyptic number.
111010443132 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
111010443132 is an abundant number, since it is smaller than the sum of its proper divisors (148013924204).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
111010443132 is a wasteful number, since it uses less digits than its factorization.
111010443132 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 9250870268 (or 9250870266 counting only the distinct ones).
The product of its (nonzero) digits is 288, while the sum is 21.
Adding to 111010443132 its reverse (231344010111), we get a palindrome (342354453243).
The spelling of 111010443132 in words is "one hundred eleven billion, ten million, four hundred forty-three thousand, one hundred thirty-two".
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