Base | Representation |
---|---|
bin | 10000001001110111110… |
… | …001011110010001100110 |
3 | 10221010101112201210211221 |
4 | 100021313301132101212 |
5 | 121142001410121014 |
6 | 2205551123450554 |
7 | 143126404660234 |
oct | 20116761362146 |
9 | 3833345653757 |
10 | 1110111020134 |
11 | 398882804086 |
12 | 15b191b26a5a |
13 | 808b579721c |
14 | 3ba30289954 |
15 | 1dd2348db24 |
hex | 10277c5e466 |
1110111020134 has 4 divisors (see below), whose sum is σ = 1665166530204. Its totient is φ = 555055510066.
The previous prime is 1110111020111. The next prime is 1110111020147. The reversal of 1110111020134 is 4310201110111.
It is a semiprime because it is the product of two primes.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 277527755032 + ... + 277527755035.
It is an arithmetic number, because the mean of its divisors is an integer number (416291632551).
Almost surely, 21110111020134 is an apocalyptic number.
1110111020134 is a deficient number, since it is larger than the sum of its proper divisors (555055510070).
1110111020134 is an equidigital number, since it uses as much as digits as its factorization.
1110111020134 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 555055510069.
The product of its (nonzero) digits is 24, while the sum is 16.
Adding to 1110111020134 its reverse (4310201110111), we get a palindrome (5420312130245).
The spelling of 1110111020134 in words is "one trillion, one hundred ten billion, one hundred eleven million, twenty thousand, one hundred thirty-four".
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