Base | Representation |
---|---|
bin | 10000001001110111111… |
… | …001011101010100001101 |
3 | 10221010101200200011012201 |
4 | 100021313321131110031 |
5 | 121142002424111412 |
6 | 2205551240401501 |
7 | 143126431526023 |
oct | 20116771352415 |
9 | 3833350604181 |
10 | 1110113113357 |
11 | 398883a03816 |
12 | 15b192776291 |
13 | 808b604ac11 |
14 | 3ba30672713 |
15 | 1dd23753e57 |
hex | 10277e5d50d |
1110113113357 has 2 divisors, whose sum is σ = 1110113113358. Its totient is φ = 1110113113356.
The previous prime is 1110113113309. The next prime is 1110113113367. The reversal of 1110113113357 is 7533113110111.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 804341716201 + 305771397156 = 896851^2 + 552966^2 .
It is a cyclic number.
It is not a de Polignac number, because 1110113113357 - 215 = 1110113080589 is a prime.
It is a super-2 number, since 2×11101131133572 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1110113113367) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 555056556678 + 555056556679.
It is an arithmetic number, because the mean of its divisors is an integer number (555056556679).
Almost surely, 21110113113357 is an apocalyptic number.
It is an amenable number.
1110113113357 is a deficient number, since it is larger than the sum of its proper divisors (1).
1110113113357 is an equidigital number, since it uses as much as digits as its factorization.
1110113113357 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 945, while the sum is 28.
Adding to 1110113113357 its reverse (7533113110111), we get a palindrome (8643226223468).
The spelling of 1110113113357 in words is "one trillion, one hundred ten billion, one hundred thirteen million, one hundred thirteen thousand, three hundred fifty-seven".
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