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111012197026693 is a prime number
BaseRepresentation
bin11001001111011100001010…
…100100011100101110000101
3112120001122212212211100202111
4121033130022210130232011
5104022310434414323233
61032034144350541021
732245236505344304
oct3117341244345605
9476048785740674
10111012197026693
1132410010159836
121054aaa8207771
1349c3536487651
141d5b03a21243b
15cc7a36b67acd
hex64f70a91cb85

111012197026693 has 2 divisors, whose sum is σ = 111012197026694. Its totient is φ = 111012197026692.

The previous prime is 111012197026657. The next prime is 111012197026697. The reversal of 111012197026693 is 396620791210111.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 110685907023169 + 326290003524 = 10520737^2 + 571218^2 .

It is a cyclic number.

It is not a de Polignac number, because 111012197026693 - 225 = 111012163472261 is a prime.

It is a super-2 number, since 2×1110121970266932 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (111012197026697) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55506098513346 + 55506098513347.

It is an arithmetic number, because the mean of its divisors is an integer number (55506098513347).

Almost surely, 2111012197026693 is an apocalyptic number.

It is an amenable number.

111012197026693 is a deficient number, since it is larger than the sum of its proper divisors (1).

111012197026693 is an equidigital number, since it uses as much as digits as its factorization.

111012197026693 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 244944, while the sum is 49.

The spelling of 111012197026693 in words is "one hundred eleven trillion, twelve billion, one hundred ninety-seven million, twenty-six thousand, six hundred ninety-three".