Base | Representation |
---|---|
bin | 11001001111011101000001… |
… | …101001100011010010111111 |
3 | 112120001202021021122201102202 |
4 | 121033131001221203102333 |
5 | 104022314333001024411 |
6 | 1032034420201142115 |
7 | 32245301426053313 |
oct | 3117350151432277 |
9 | 476052237581382 |
10 | 111013121111231 |
11 | 32410444841169 |
12 | 1054b10578a93b |
13 | 49c3652a64631 |
14 | 1d5b0c6c3bb43 |
15 | cc7a8cd5083b |
hex | 64f741a634bf |
111013121111231 has 2 divisors, whose sum is σ = 111013121111232. Its totient is φ = 111013121111230.
The previous prime is 111013121111219. The next prime is 111013121111371. The reversal of 111013121111231 is 132111121310111.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 111013121111231 - 210 = 111013121110207 is a prime.
It is a super-2 number, since 2×1110131211112312 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (111013121111201) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55506560555615 + 55506560555616.
It is an arithmetic number, because the mean of its divisors is an integer number (55506560555616).
Almost surely, 2111013121111231 is an apocalyptic number.
111013121111231 is a deficient number, since it is larger than the sum of its proper divisors (1).
111013121111231 is an equidigital number, since it uses as much as digits as its factorization.
111013121111231 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 36, while the sum is 20.
Adding to 111013121111231 its reverse (132111121310111), we get a palindrome (243124242421342).
The spelling of 111013121111231 in words is "one hundred eleven trillion, thirteen billion, one hundred twenty-one million, one hundred eleven thousand, two hundred thirty-one".
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