Base | Representation |
---|---|
bin | 10000001001111001000… |
… | …101110100011101111011 |
3 | 10221010110002100011102202 |
4 | 100021321011310131323 |
5 | 121142023040144011 |
6 | 2205553233420415 |
7 | 143130063630623 |
oct | 20117105643573 |
9 | 3833402304382 |
10 | 1110133131131 |
11 | 398894236432 |
12 | 15b19940a70b |
13 | 808ba23945b |
14 | 3ba331a3883 |
15 | 1dd253aa23b |
hex | 1027917477b |
1110133131131 has 2 divisors, whose sum is σ = 1110133131132. Its totient is φ = 1110133131130.
The previous prime is 1110133131101. The next prime is 1110133131157. The reversal of 1110133131131 is 1311313310111.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1110133131131 - 222 = 1110128936827 is a prime.
It is a super-2 number, since 2×11101331311312 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1110133131101) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 555066565565 + 555066565566.
It is an arithmetic number, because the mean of its divisors is an integer number (555066565566).
Almost surely, 21110133131131 is an apocalyptic number.
1110133131131 is a deficient number, since it is larger than the sum of its proper divisors (1).
1110133131131 is an equidigital number, since it uses as much as digits as its factorization.
1110133131131 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 81, while the sum is 20.
Adding to 1110133131131 its reverse (1311313310111), we get a palindrome (2421446441242).
The spelling of 1110133131131 in words is "one trillion, one hundred ten billion, one hundred thirty-three million, one hundred thirty-one thousand, one hundred thirty-one".
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