Base | Representation |
---|---|
bin | 10000001001111101000… |
… | …101101101101001110001 |
3 | 10221010121202120020012101 |
4 | 100021331011231221301 |
5 | 121142142223241311 |
6 | 2210004031300401 |
7 | 143131540046122 |
oct | 20117505555161 |
9 | 3833552506171 |
10 | 1110200212081 |
11 | 398919093334 |
12 | 15b1b797a701 |
13 | 808cb0c541c |
14 | 3ba3c066049 |
15 | 1dd2b20aec1 |
hex | 1027d16da71 |
1110200212081 has 2 divisors, whose sum is σ = 1110200212082. Its totient is φ = 1110200212080.
The previous prime is 1110200212063. The next prime is 1110200212111. The reversal of 1110200212081 is 1802120020111.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1095771397681 + 14428814400 = 1046791^2 + 120120^2 .
It is a cyclic number.
It is not a de Polignac number, because 1110200212081 - 29 = 1110200211569 is a prime.
It is a super-2 number, since 2×11102002120812 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1110200212061) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 555100106040 + 555100106041.
It is an arithmetic number, because the mean of its divisors is an integer number (555100106041).
Almost surely, 21110200212081 is an apocalyptic number.
It is an amenable number.
1110200212081 is a deficient number, since it is larger than the sum of its proper divisors (1).
1110200212081 is an equidigital number, since it uses as much as digits as its factorization.
1110200212081 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 64, while the sum is 19.
Adding to 1110200212081 its reverse (1802120020111), we get a palindrome (2912320232192).
The spelling of 1110200212081 in words is "one trillion, one hundred ten billion, two hundred million, two hundred twelve thousand, eighty-one".
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