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11102020111241 is a prime number
BaseRepresentation
bin1010000110001110001111…
…1101110000101110001001
31110022100020212111022012222
42201203203331300232021
52423343414122024431
635340110404343425
72224044256625063
oct241434375605611
943270225438188
1011102020111241
1135a0381a18534
1212b37900a4b75
13626bba5cca97
142a54aaa08733
15143bc7e2a57b
hexa18e3f70b89

11102020111241 has 2 divisors, whose sum is σ = 11102020111242. Its totient is φ = 11102020111240.

The previous prime is 11102020111181. The next prime is 11102020111253. The reversal of 11102020111241 is 14211102020111.

11102020111241 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 8191021104016 + 2910999007225 = 2861996^2 + 1706165^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11102020111241 is a prime.

It is not a weakly prime, because it can be changed into another prime (11102020111291) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5551010055620 + 5551010055621.

It is an arithmetic number, because the mean of its divisors is an integer number (5551010055621).

Almost surely, 211102020111241 is an apocalyptic number.

It is an amenable number.

11102020111241 is a deficient number, since it is larger than the sum of its proper divisors (1).

11102020111241 is an equidigital number, since it uses as much as digits as its factorization.

11102020111241 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 32, while the sum is 17.

Adding to 11102020111241 its reverse (14211102020111), we get a palindrome (25313122131352).

The spelling of 11102020111241 in words is "eleven trillion, one hundred two billion, twenty million, one hundred eleven thousand, two hundred forty-one".