Base | Representation |
---|---|
bin | 11001001111100011100111… |
… | …101001101001000100001101 |
3 | 112120002102112200221102122020 |
4 | 121033203213221221010031 |
5 | 104022423332441320023 |
6 | 1032041550514240353 |
7 | 32245642036123323 |
oct | 3117434751510415 |
9 | 476072480842566 |
10 | 111020201120013 |
11 | 32413448272599 |
12 | 105505608860b9 |
13 | 49c4210801943 |
14 | 1d5b599263d13 |
15 | cc7d546c0de3 |
hex | 64f8e7a6910d |
111020201120013 has 32 divisors (see below), whose sum is σ = 153148407939072. Its totient is φ = 71463699792000.
The previous prime is 111020201120009. The next prime is 111020201120053. The reversal of 111020201120013 is 310021102020111.
It is not a de Polignac number, because 111020201120013 - 22 = 111020201120009 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 111020201119974 and 111020201120001.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (111020201120053) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 92352856 + ... + 93547262.
It is an arithmetic number, because the mean of its divisors is an integer number (4785887748096).
Almost surely, 2111020201120013 is an apocalyptic number.
It is an amenable number.
111020201120013 is a deficient number, since it is larger than the sum of its proper divisors (42128206819059).
111020201120013 is a wasteful number, since it uses less digits than its factorization.
111020201120013 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1196705.
The product of its (nonzero) digits is 24, while the sum is 15.
Adding to 111020201120013 its reverse (310021102020111), we get a palindrome (421041303140124).
The spelling of 111020201120013 in words is "one hundred eleven trillion, twenty billion, two hundred one million, one hundred twenty thousand, thirteen".
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