Base | Representation |
---|---|
bin | 11001001111100011101110… |
… | …001101001110010111001101 |
3 | 112120002102211100220120001211 |
4 | 121033203232031032113031 |
5 | 104022424044121023432 |
6 | 1032042005443534421 |
7 | 32245644543050152 |
oct | 3117435615162715 |
9 | 476072740816054 |
10 | 111020311111117 |
11 | 324134a4368531 |
12 | 1055059168a411 |
13 | 49c422a532c35 |
14 | 1d5b5a9ad6229 |
15 | cc7d5e19ad47 |
hex | 64f8ee34e5cd |
111020311111117 has 2 divisors, whose sum is σ = 111020311111118. Its totient is φ = 111020311111116.
The previous prime is 111020311111093. The next prime is 111020311111121. The reversal of 111020311111117 is 711111113020111.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 84948554296516 + 26071756814601 = 9216754^2 + 5106051^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-111020311111117 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (111020311111217) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55510155555558 + 55510155555559.
It is an arithmetic number, because the mean of its divisors is an integer number (55510155555559).
Almost surely, 2111020311111117 is an apocalyptic number.
It is an amenable number.
111020311111117 is a deficient number, since it is larger than the sum of its proper divisors (1).
111020311111117 is an equidigital number, since it uses as much as digits as its factorization.
111020311111117 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 42, while the sum is 22.
Adding to 111020311111117 its reverse (711111113020111), we get a palindrome (822131424131228).
The spelling of 111020311111117 in words is "one hundred eleven trillion, twenty billion, three hundred eleven million, one hundred eleven thousand, one hundred seventeen".
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