Base | Representation |
---|---|
bin | 1010000110001110100101… |
… | …1001001111001101101111 |
3 | 1110022100111012220002122211 |
4 | 2201203221121033031233 |
5 | 2423344110431400421 |
6 | 35340123420551251 |
7 | 2224046444104231 |
oct | 241435131171557 |
9 | 43270435802584 |
10 | 11102111200111 |
11 | 35a0419382998 |
12 | 12b37b66b2527 |
13 | 626c03443519 |
14 | 2a54b8b5a251 |
15 | 143bd0e1e9e1 |
hex | a18e964f36f |
11102111200111 has 2 divisors, whose sum is σ = 11102111200112. Its totient is φ = 11102111200110.
The previous prime is 11102111200049. The next prime is 11102111200127. The reversal of 11102111200111 is 11100211120111.
It is a strong prime.
It is an emirp because it is prime and its reverse (11100211120111) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 11102111200111 - 231 = 11099963716463 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 11102111200091 and 11102111200100.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11102111200151) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5551055600055 + 5551055600056.
It is an arithmetic number, because the mean of its divisors is an integer number (5551055600056).
Almost surely, 211102111200111 is an apocalyptic number.
11102111200111 is a deficient number, since it is larger than the sum of its proper divisors (1).
11102111200111 is an equidigital number, since it uses as much as digits as its factorization.
11102111200111 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4, while the sum is 13.
Adding to 11102111200111 its reverse (11100211120111), we get a palindrome (22202322320222).
The spelling of 11102111200111 in words is "eleven trillion, one hundred two billion, one hundred eleven million, two hundred thousand, one hundred eleven".
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