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11102120153623 is a prime number
BaseRepresentation
bin1010000110001110100111…
…1011011001001000010111
31110022100111211201222120101
42201203221323121020113
52423344120224403443
635340124340514531
72224046613154612
oct241435173311027
943270454658511
1011102120153623
1135a0423438894
1212b37b96aba47
13626c05259965
142a54ba00b179
15143bd1adc84d
hexa18e9ed9217

11102120153623 has 2 divisors, whose sum is σ = 11102120153624. Its totient is φ = 11102120153622.

The previous prime is 11102120153617. The next prime is 11102120153767. The reversal of 11102120153623 is 32635102120111.

11102120153623 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 11102120153623 - 217 = 11102120022551 is a prime.

It is a super-2 number, since 2×111021201536232 (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 11102120153591 and 11102120153600.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11102120153603) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5551060076811 + 5551060076812.

It is an arithmetic number, because the mean of its divisors is an integer number (5551060076812).

Almost surely, 211102120153623 is an apocalyptic number.

11102120153623 is a deficient number, since it is larger than the sum of its proper divisors (1).

11102120153623 is an equidigital number, since it uses as much as digits as its factorization.

11102120153623 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2160, while the sum is 28.

Adding to 11102120153623 its reverse (32635102120111), we get a palindrome (43737222273734).

The spelling of 11102120153623 in words is "eleven trillion, one hundred two billion, one hundred twenty million, one hundred fifty-three thousand, six hundred twenty-three".